1.1t^2-9.5t=0

Solution for 1.1t^2-9.5t=0 equation:

1.1t^2-9.5t=0

a = 1.1; b = -9.5; c = 0;
Δ = b2-4ac
Δ = -9.52-4·1.1·0
Δ = 90.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9.5)-\sqrt{90.25}}{2*1.1}=\frac{9.5-\sqrt{90.25}}{2.2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9.5)+\sqrt{90.25}}{2*1.1}=\frac{9.5+\sqrt{90.25}}{2.2}
$